8. In this simulation, the reaction generates two products: A B + C At each step

Question

8. In this simulation, the reaction generates two products: A B + C At each step, let one-tenth of the A molecules be transformed into B and C. Because B and C need to come together to form A, the fraction that is transformed involves the product of the concentration of B times that of C. Set the fraction of [B] X [C], molecules that are transformed into A molecules to 0.025. Start with 100 molecules of A and 10 molecules of C. What are the equilibrium concentrations? How many cycles does it take to arrive at equilibrium?

Explanation / Answer

Initial amount of A = 100 molecules

Initial amount of C = 10 molecules

Initial amount of B = 0 molecules

In the first cycle, (1/10)*100 = 10 molecules of A converted to 10 molecules of B and 20 molecules of C (total C)

Therefore, [B]*[C] = 10*20 = 200 and 0.025*200 = 5 molecules of A is produced.

Number of cycles it takes for A to completely transform into B and C = 10 cycles and in that 10 cycles number of A molecules formed is 50, which takes another 5 cycles and so on.

total cycles = 10 + 5 + 2 + 1 = 18

Therefore, [A] = 5

[B] = 0.1*(100-5) = 95

[C] = 0.1*(100-5) + 10 = 105

Related Questions

Navigate

• Browse (All)
• Browse 8
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.