Molar Solubility and solubility Product of Calcium Hydroxide: 1. Volume of Satur

ID: 938206 • Letter: M

Question

Molar Solubility and solubility Product of Calcium Hydroxide:

1. Volume of Saturated Ca(OH)2 solution (mL) = 25.0 mL

2. Concentration of Standardized HCL solution (mol/L) = 0.05 mol/L

3. Buret reading, initial (mL) = 50.0 mL

4. Buret reading, final (mL) = 32.5 mL

5. Volume of HCL added (mL) = 17.5 mL

6. Moles of HCL added (mol) = (concentration of HCl)(Volume of HCl) = (0.05)(19.1) = 0.875 mol.

7.Moles of OH- in saturated solution (mol)=8.75x10^-4

Can someone please help me with questions 8-15 please!?

8.the [OH-] equilibrium (mol/L),

9.[Ca2+] equilibrium (mol/L),

10.Molar solubility of Ca(OH)2 (mol/L),

11.Average molar solubility of Ca(OH)2 (mol/L),

12.Ksp of Ca(OH)2,

13.Average Ksp

14.Satandard deviation of Ksp, and

15.The Relative Standard deviation of Ksp (%RSD)

Thank you!!

1. Moles of OH- = 8.75 x 10-4

Molarity (mol / L) = No. of moles of solute / Volume of solution(in L)

Volume of solution = volume of Ca(OH)2 + Volume of HCl added = 25 + 17.5 = 42.5 ml = 0.0425 L

Molarity = 8.75 x 10-4/ 0.0425 = 205.88 x 10-4 M = 0.0205 M

[OH-] = 0.0205 M

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