Determine the value of the equilibrium constant, K goal, for the reaction N2(g)+
ID: 939042 • Letter: D
Question
Determine the value of the equilibrium constant, Kgoal, for the reaction
N2(g)+H2O(g)NO(g)+12N2H4(g), Kgoal=?
by making use of the following information:
Express your answer numerically.
part b
Determine the equilibrium constant, Kgoal, for the reaction
4PCl5(g)P4(s)+10Cl2(g), Kgoal=?
by making use of the following information:
P4(s)+6Cl2(g)4PCl3(g), K1=2.00×1019
PCl5(g)PCl3(g)+Cl2(g), K2=1.13×102
Express your answer numerically.
1. N2(g)+O2(g)2NO(g), K1 = 4.10×1031 2. N2(g)+2H2(g)N2H4(g), K2 = 7.40×1026 3. 2H2O(g)2H2(g)+O2(g), K3 = 1.06×1010Explanation / Answer
1) eq(1) + eq(2) + eq(3) gives
2N2 + 2H2O ---> 2NO + N2H4 , K = K1 x K2 x K3 = 3.2 x 10^ -66
when reaction is halved we get our required equation Kgoal = K^ 1/2 = ( 3.2x10^-66)^1/2 = 1.79 x 10^ -33
2) 4eq(2) - eq (1) gives
4PCl45 <--> P4 (s) + 10Cl2 ( g)
K = k2^4 / k1 = ( 1.13x10^-2)^4 / ( 2x10^19) = 8.15 x 10^ -28
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