Match the chemical equation with reaction type: Single Displacement, Double Disp

Question

Match the chemical equation with reaction type: Single Displacement, Double Displacement, Combination (Synthesis), or Decomposition. Cu(NO_2)_2(aq) + 2NaOH(aq) Cu(OH)_2(s) + 2NaNO_3(aq) What mass of Cu metal is required to react with 5.5 drops of 16M HNO_3? Assume 20 drops = 1 mL. Cu (MM 63.54 g/mol), (16M = 16 mol/L) Cu(s) + 4HNO_3(aq) rightarrow Cu(NO_3)_2(ag) + 2NO_2(g) + 2H_2O(1) Show entire calculation. Box in answer. Give answer to 2 significant figures. Include unit. One of the steps is performed in the fume hood because of the evolution of a toxic brown gas, nitrogen dioxide. This is during formation of.Include the correct formula of the product in the copper experiment.

Explanation / Answer

2. Match the chemical equation with reaction type:

Cu(NO3)2 (aq) + 2 NaOH (aq) <---> Cu(OH)2 (s) + 2 NaNO3 (aq) Double displacement

Cu(OH)2 (s) <---> CuO (s) + H2O (g) Decomposition

CuO (s) + H2SO4 (aq) <---> CuSO4 (aq) + H2O (l) Double displacement

CuSO4 (aq) + Mg (s) <---> Cu (s) + MgSO4 (aq) Single displacement

Mg (s) + H2SO4 (aq) <---> H2 (g) + MgSO4 (aq) Single displacement   

3. What mass of Cu metal is required to react with 5.5 drops of 16 M HNO3?

20 drops= 1 mL

Cu (MM= 63.54 g/mol

16 M HNO3= 16 mol/L HNO3

Cu(s) + 4HNO3 (aq) ---> Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O (l)

V HNO3

5.5 drops HNO3 x   1 mL = 0.275 mL HNO3

20 drops

Mol HNO3

16 mol HNO3 x 0,275 mL HNO3 x 1 L   =   4.4x10-3 mol HNO3

L 1000 mL

1 mole of Cu (s) reacts with 4 moles of HNO3, then:

1 mol Cu (s) x 4,4x10-3 mol HNO3 = 1.1x10-3 mol Cu (s)

4 mol HNO3 (aq)

Then we can calculate the mass of Cu (s) that corresponds to 1.1x10-3 moles of Cu (s) as follows:

63,54 g Cu (s)  x 1.1x10-3 mol Cu (s) x 1000 mg = [ 69,89 mg Cu (s) ]

mol 1 g

69,89 mg of Cu (s) are required to react with 5.5 drops of 16 M HNO3

5. One of the steps is performed in the fume hood because of the evolution of a toxic brown gas, nitrogen dioxide. This is during the formation of copper (II) nitrate.

Copper is oxidized by concentrated nitric acid, HNO3, to produce Cu2+ ions; the nitric acid is reduced to nitrogen dioxide.

Cu(s) + 4HNO3 (aq) ---> Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O (l)

Toxic brown gas

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