A certain rifle bullet has a mass of 6.93 g. Calculate the de Broglie wavelength

Question

A certain rifle bullet has a mass of 6.93 g. Calculate the de Broglie wavelength of the bullet traveling at 1721 miles per hour. Physical constants can be found here (Please see Chart below).

Hint: Miles per hour is not the SI unit for velocity. Below are some useful relationships to obtain the velocity of the bullet in correct SI units. (Please see below exampels of unites)

Physical Constants Quantity Symbol Value FAQ: Do I need all these decimal places? speed of light in a vacuum2.99792458x108 m/s (exact) Planck's constant universal gas constant When doing a calculation, the constants should be more precise than the other values. For example, if the given values in your homework question all have thre significant figures, then c 2.998x108 m/s is sufficient because it will not limit the precision of your answer h 6.62606957x10-34 J-s R 0.082057 L-atm/(mol-K) 8.3145 J/(mol-k) 8.3145 m Pa/(mol.K) 8.3145 L-kPa/(mol-k) 0.083145 L.bar/(mol-K) 62.364 L-Torr/(mol K) NA 6.02214129x1023 formula units/mol the Avogadro constant mass of an electron me 9.10938291x10-28 g mp 1.672621777x10-24 mn 1.674927351x10-24g 5.4858x104 amu mass of a proton 1.007276467 amu mass of a neutron 1.008664916 amu charge on an electron Boltzmann constant Faraday constant Rydberg constant 1.602176565× 10-19 C k |1.3806488×10-23 J/K F 96485 C/mol of electrons H1097373x107 m1 2.179872x10-18 3.289842x1015 s-1 Electric constant | 8.854 187817x 10-12 F/m 8.854187817× 10-12 C2/(Mn)

Explanation / Answer

Wave length(L) = h/P

velocity = 1721 milesper hour = 769.3558 m/s

m = 6.93 gram = 6.93*10^(-3) kg

l = (6.625*10^(-34))/(6.93*10^(-3)*769.3558)

   = 1.24*10^(-34) m

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