To solve stoichiometry problems, you must always calculate numbers of moles. Rec

Question

To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is eqyal to the concentration in moles per liter. M= mol/L. When solutions of silver and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO_3(aq) + CaCl_2(aq)rightarrow2AgCl(s) + Ca(NO_3)_2(aq) What mass of silver chloride can be produced from 1.86 L of a 0.237 M solution of silver nitrate? Express your answer with the appropriate units. the reaction described in Part A required 3.82 L of calcium chloride. What is the concentration of this calcium chloride solution? Express your answer with the appropriate units.

Explanation / Answer

Ok to calculate the concentration you need two things

the moles and the volume in Liters.

You already have the volume (3.82 L)

To calculate the moles you need to calculate the moles of the AgCl.

In the part A. you calculate the moles of the AgNO3 with 1.86 L and 0.237 M

Then molesAgNO3= M x V = 0.44 moles of AgNO3

Now if we do the stequiometric relation.

2 moles of AgNO3 react with 1 mole of CaCl. Then 0.441 moles of AgNO3 will react with X moles of CaCl

then Xmoles of CaCl= 0.441/2 = 0.22 moles of CaCl

Now we can calculate the concentration of CaCl.

M= 0.22moles/3.82 L = 0.057 mol/L 0 0.057 M

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