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So I\'m trying to solve this problem but keep getting the incorrect answer, what

ID: 943018 • Letter: S

Question

So I'm trying to solve this problem but keep getting the incorrect answer, what am I doing wrong? What is the correct answer?

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Use the References to access important values if needed for this question.

A voltaic cell is constructed from a standard Cr3+|Cr half cell (E°red = -0.740V) and a standard I2|I- half cell  (E°red = 0.535V).

The anode reaction is:



The cathode reaction is:



The spontaneous cell reaction is:



The cell voltage is 1.28 V.

Enter electrons as e-. Use smallest possible integer coefficients. If a box is not needed, leave it blank

Explanation / Answer

given

Cr+3/Cr and I2/I-

we know that

the half cell with more positive reduction potential is cathode

and

the half cell with less positive reduction potential is anode

so

in this case

Anode reaction is

Cr(S) ---> Cr+3 + 3e-

cathode reaction is

I2 + 2e- ----> 2I-

and

the cell reaction is

2Cr(s) + 3I2 (s) ---> 2 Cr+3 (aq) + 6I- aq)


finally

we know that

Eo cell = Eo cathode - Eo anode

so

Eo cell = 0.535 - (-0.74)

Eo cell = 1.275

so

the cell voltage is 1.275 V

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