Consider the following equilibrium. Cu +2 + 4 NH 3 Cu(NH 3 ) 4 +2 The copper ion

Question

Consider the following equilibrium. Cu+2 + 4 NH3 Cu(NH3)4+2
The copper ion in solution is light blue. The Cu(NH3)4+2 ion is a deep blue. The tube on the left contains only copper ions. Identify what chemical was added to produce the results shown in the center tube. Identify what chemical may have been added to the center tube to produce the results shown in the right tube and write out the reaction Consider the following equilibrium. Cu+2 + 4 NH3 Cu(NH3)4+2
The copper ion in solution is light blue. The Cu(NH3)4+2 ion is a deep blue. The tube on the left contains only copper ions. Identify what chemical was added to produce the results shown in the center tube. Identify what chemical may have been added to the center tube to produce the results shown in the right tube and write out the reaction Consider the following equilibrium. Cu+2 + 4 NH3 Cu(NH3)4+2
The copper ion in solution is light blue. The Cu(NH3)4+2 ion is a deep blue. The tube on the left contains only copper ions. Identify what chemical was added to produce the results shown in the center tube. Identify what chemical may have been added to the center tube to produce the results shown in the right tube and write out the reaction

Explanation / Answer

Cu+2(light blue) + 4 NH3 ----> [Cu(NH3)4]+2 (deepblue)

[Cu(NH3)4]+2 + Zn+2-------->[Zn(NH3)]+2(colourless) + Cu+2 (light blue)

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