Due to the widespread use of sodium hydrogen Due to the widespread use of sodium

Question

Due to the widespread use of sodium hydrogen Due to the widespread use of sodium hydrogen carbonate carbonate (commonly called baking soda or sodium bicarbonate) in many food products, the thermal decomposition reaction has been studied extensively by food chemists Baking soda is used to prepare cakes in order to insure that cakes "rise" as they bake As the temperature of the cake batter reaches approximately 500C, the baking soda decomposes and soda is especaly popular i pancakes and waes s carbon dioxide is released. The use of baking soda is especially popular in pancakes and waffles since the high cooking temperatures of 350-4500F (175-2300c) cause the carbon dioxide to be liberated before the dough has set. Thus, the batter rises before it sets, and we get a light and tasty finished product There are three possible chemical reactions that could be occurring during the baking process All three of these reactions shown below are theoretically possible, yet only one reaction actually occurs Possible Decomposition Reactions sodium hydrogen carbonate sodumhydroode + bon donde solid) (solid) solid (gas) sodurn hydrogen carbonate--> sodium ande bon donde water (solid) (sold) (gas) sodum hydrogen carbonate sodium, borate ion solld) (sold) (pas) Problem The goal of this lab is for you to experimentally determine which of these three reactions is correct. Your job is to use stoichiometry to determine which decomposition reaction is actualy occurring inside the crucible Crucibles (lid not required) .Baking Soda . Balances * Crucible tongs e metal spatula Students should wear safety goggles throughout this experiment

Explanation / Answer

Let's write the whole reaction and then answer the blank space:

NaHCO3 --------> Na2CO3 + CO2 + H2O

Now, balancing the equation:

2NaHCO3 --------> Na2CO3 + CO2 + H2O

Now, I'll put the sub parts and separate each compound by a ; in this way, you'll know which compound is following the order in the reaction:

a) Both; Both; Covalent; Covalent

b) Na+ HCO3-; 2Na+ CO32-

c) Already written in the reaction balanced.

Now the GFM is the molar mass of each component, for that, you'll need the atomic weights which are:

Na: 23 g/mol; H = 1 g/mol; O = 16 g/mol; C = 12 g/mol

Now, I'll calculate the molar mass and then replace these in the blank spaces:

NaHCO3 = 23+1+12+3(16) = 84 g/mol

Na2CO3 = 2(23)+12+3(16) = 106 g/mol

CO2 = 12+2(16) = 44 g/mol

NaOH = 23+1+16 = 40 g/mol

H2O = 2(1)+16 = 18 g/mol

Na2O = 2(23)´16 = 62 g/mol

Hope this helps

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