Beryllium reacts with hydrochloric acid completely. ln the above reaction, the t

Question

Beryllium reacts with hydrochloric acid completely. ln the above reaction, the theoretical yield of beryllium chloride was 10.7 grams. If my actual yield 3S 4.5 grams, what was my percent yield? How much hydrogen gas would you expect to have produced if you had a perfect yield? FeBr_2 + KCl rightarrow FeCl_2 + KBr What is my theoretical yield of iron (II) chloride if 1 start with 34 grams of iron (II) bromide? What is my percent yield of iron (II) chloride if my actual yield is 4.0 grams? Speculate on a few reasons why a chemist may not get a perfect percent yield.

Explanation / Answer

Be(s) + 2HCl(aq) ----> BeCl2(aq) + H2(g)

1 mol Be(s) = 2 mol HCl(aq) = 1 mol BeCl2(aq) = 1 mol H2(g)

a)

percent yield = practical yield / theoretical yield*100

        = 4.5/10.7*100

        = 42.056%

b) No of mol of Becl2 produced = 10.7/79.9182 = 0.134 mol

so that,

No of mol of H2 produced = 0.134 mol

mass of H2 = 0.134*2 = 0.268 grams

4. FeBr2 + 2KCl ----> FeCl2 + 2KBr

No of mol of FeBr2 = 34/215.65 = 0.158 mol

No of mol of Fecl2 = 0.158 mol

mass of Fecl2 = 0.158*126.7510 = 20.02 grams

percent yield = practical yield / theoretical yield*100

    = 4/20.02*100 = 19.98 %

because there may be man made errors , technical errors.

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