This 15 Day Challenge w x S. University of Maine at Fax G dell screenshot Google

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This 15 Day Challenge w x S. University of Maine at Fax G dell screenshot Google × M Periwinkles Group Pro ec × Consider This Reaction D × Peri inkles Group Project X c Dwww.saplinglearning.com/ibiscms/mod/ibis/view.php?id=2200367 Sapling Learning Logout @ Help Jump to.. sapling Learning University of Maine at Farmington-CHY 142-Spring16-SHERROD Activities and Due Dates HW 12 My Assignment Resources Last Attempt Attempts Score 3/7/2016 06:00 PM 829/1003/3/2016 1 1:08 PM Print Calculator Periodic Table Available From: 1/17/2016 06:00 PM Question 24 of 38 Due Date: 3/7/2016 06:00 PM 15 Allowed with 5% of the points possible deducted per day until 03/27/2016 06:00 PM ol yhus yeachon hal points wouie youpna the activation energy 16 Consider this reaction data If you were going to graphically determine the activation energy this reaction, what points would you plot? 17 A >products 18 T (K) k (s) 325 825 Points Possible: 100 To avoid rounding errors, use at least three significant figures in all values. 0.381 point 1: n Grade Category: Graded 0.623 point 2 Tools You can check your answers. Determine the rise, run, and slope of the line formed by these points. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up. You lose 5% of the points available to each answer in your question for each incorrect attempt at that What is the activation energy of this reaction? O eTextbook OHelp With This Topic O Web Help &Videos; OTechnical Support and Bug Reports 28 J/ mol 30 Previous Give Up & View Solution Check Answer Next Exit Hint Copyright © 2011-2016 Sapilng Leaming Inc.-47 6:05 PM 3/4/2016

Explanation / Answer

From K= Koe(-Ea/RT)

ln K= lnKo-Ea/RT

so a plot of lnK vs 1/T gives a straight line whose slope is –Ea/R.

                        T (K)                1/T                          lnK

                        325                0.003077            -0.96496

                       825               0.001212                -0.47321

Rise = -0.47321+0.96496=0.491747

run= 0.003077-0.001212=0.001865

Ea/R= 0.491747/0.001865 = slope =263.7

Ea =263.7*8.314=2192.402 Joules/mole

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