The following reaction is used in a device for testing the breath of a person fo
ID: 951392 • Letter: T
Question
The following reaction is used in a device for testing the breath of a person for the presence of ethanol. Identify the oxidizing and reducing agents, the substance oxidized, and the substance reduced. What is the oxidation number of Mn in BaMnO_4? 0 +3 +6 +12 2. Which of the following reactions are oxidation-reduction reactions? NaOH(aq) + HNO_3(aq) rightarrow NaNO_3(aq) + H_2O(l) Cu(s) + Cl_2(g) rightarrow CuCI_2(s) Na_2CO_3(aq) + 2 HCIO_4(aq) rightarrow CO_2(g) + H_2O(l) + 2 NaCIO_4(aq) all of them 2,3, and 4 2 and 4 2 only 3. In which of the manganese compounds below does Mn have the highest oxidation number? Mn_2O_2 Mn_2O3 KMnO_4 MnCI_2Explanation / Answer
When oxidation state decreases it becomes reduced it acts as oxidising agent.
dichromate ion Cr2O72- has Cr in +6 state while product we have Cr3+
hence dichromate ion is reduced and it acts as oxidising agent
Ethanol is oxidised to acteic acid , it acts as reducing agent.
1) In reaction 1 Na is +1 state both sides O and H also didinot change , hence its not option
In reaction 2 Cu is oxidised to 0 to +2 , while Cl is reduced from 0 to -1 , ( CuCl2 has Cu2+ and Cl-)
hence its a option
Reaction 3 is acid base reaction with no oxidation state change
Reaction 4 has change in oxidation state s , I2 has 0 while 2I- has -1 oxidation state ,
Hence reactions 2,4 are oxidation -reduction reaction.
3) MnO2 has Mn +4 as O will have -2.
Mn2O3 has Mn+3, KMnO4 has Mn+7 , MnCl2 has Mn+2
hence correction option is KMnO4 where Mn has highest oxidation state
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