When mixed, aqueous solutions of aluminum nitrate, Al(NO 3 ) 3 , and ammonium ca

Question

When mixed, aqueous solutions of aluminum nitrate, Al(NO3)3, and ammonium carbonate, (NH4)2CO3, will form a precipitate of aluminum carbonate, Al2(CO3)3. The balanced equation is:

2Al(NO3)3(aq)    +     3(NH4)2CO3(aq)     à     Al2(CO3)3(s)     +     6NH4NO3(aq)

Which of the following statements regarding this reaction is incorrect?

A)2 moles of Al(NO3)3 will react with 3 moles of (NH4)2CO3.

B)If 6 moles of (NH4)2CO3 react with sufficient Al(NO3)3, 2 moles of Al2(CO3)3 will be formed.

C)If 0.5 mole of (NH4)2CO3 react with sufficient Al(NO3)3, 3 moles of Al2(CO3)3 will be formed.

D)If 1.5 moles of Al2(CO3)3 are formed, given sufficient starting materials, then 9 moles of NH4NO3 will also be formed.

E)4 moles of Al(NO3)3 will react with 6 moles of (NH4)2CO3.

F)If 4 moles of Al(NO3)3 reacts with 9 moles of (NH4)2CO3 there will be left over (NH4)2CO3

Explanation / Answer

Incorrect statement

C) If 0.5 mole of (NH4)2CO3 react with sufficient Al(NO3)3, 3 moles of Al2(CO3)3 will be formed

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