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The major monobrominated product that results from 2,2-dimethlpropane is a prima

ID: 954611 • Letter: T

Question

The major monobrominated product that results from 2,2-dimethlpropane is a primary bromide a secondary brom.de a quaternary bromide a benzylic bromide In a carbene. the lone pair of electron resides in a(n) sp^2 orbital sp^3 orbital s orbital p orbital How many monochlorination structural products will form in the following reaction? How many distinct monochlorination products, including stereoisomers, can form in the following reaction from the reaction in number 3? 4 6 8 10 Which of the following is NOT true of free-radical halogenations reactions? (follow trends) fluorine is less selective than chlorine bromine is more selective than chlorine the reactions require either heat or light to proceed brominations are faster than chlorinations Which of these is an optically active compound? Which of these conditions will contribute to a reaction being spontaneous?

Explanation / Answer

1)

Answer is (a) a primary bromide. (only primary carbon is free)

2)

Answer is (a) a sp2 orbital.

3)

Answer is (e) 4. Since 4 different types of carbon is there in the molecule.

4)

Answer is (c) 8.

Since 4 different types of carbon is there in the molecule. So, 4+4 =8 (chlorine 4 Up and 4 down or 4R and 4S).

6)

Answer is (d)

Rest all are meso compound.

7)

Answer is (a)

If a reaction is exothermic (H is negative) and the entropy S is positive (more disorder), the free energy change is always negative and the reaction is always spontaneous.

8)

Answer is (a) 2

Since one stereo center is present so 2 steroisomers