As a technician in a large pharmaceutical research firm, you need to produce 150

ID: 956262 • Letter: A

Question

As a technician in a large pharmaceutical research firm, you need to produce 150 mL of 1.00 M potassium phosphate solution of pH = 7.03. The pKa of H2PO4^- is 7.21. You have 2.00 L KH2PO4 of 1.00 M solution and 1.50 L K2HPO4 of 1.00 M solution, as well as a carboy of pure distilled H2O . How much 1.00 M KH2PO4 will you need to make this solution? Express answer to 3 sig figs. 0 Comments

As a technician in a large pharmaceutical research firm, you need to produce 150 mL of 1.00 M potassium phosphate solution of pH = 7.03. The pKa of H2PO4^- is 7.21. You have 2.00 L KH2PO4 of 1.00 M solution and 1.50 L K2HPO4 of 1.00 M solution, as well as a carboy of pure distilled H2O . How much 1.00 M KH2PO4 will you need to make this solution? Express answer to 3 sig figs. 0 Comments

As a technician in a large pharmaceutical research firm, you need to produce 150 mL of 1.00 M potassium phosphate solution of pH = 7.03. The pKa of H2PO4^- is 7.21. You have 2.00 L KH2PO4 of 1.00 M solution and 1.50 L K2HPO4 of 1.00 M solution, as well as a carboy of pure distilled H2O . How much 1.00 M KH2PO4 will you need to make this solution? Express answer to 3 sig figs. 0 Comments
As a technician in a large pharmaceutical research firm, you need to produce 150 mL of 1.00 M potassium phosphate solution of pH = 7.03. The pKa of H2PO4^- is 7.21. You have 2.00 L KH2PO4 of 1.00 M solution and 1.50 L K2HPO4 of 1.00 M solution, as well as a carboy of pure distilled H2O . How much 1.00 M KH2PO4 will you need to make this solution? Express answer to 3 sig figs.

Explanation / Answer

pH = 7.03

pKa = 7.21

moles of potassium phosphate solution = 150 x 1 / 1000 = 0.150

KH2PO4 + K2HPO4 = 0.150 ------------> 1

pH = pKa + log [salt / base]

7.03 = 7.21 + log [ K2HPO4 / KH2PO4]

[ K2HPO4 / KH2PO4] = 0.6607

K2HPO4 = 0.6607 KH2PO4

KH2PO4 + K2HPO4 = 0.150 ------------> 1

KH2PO4 + 0.6607 KH2PO4 = 0.150

KH2PO4 moles = 0.0903

molarity = 1.00 M

volume of KH2PO4 = moles / molarity = 0.0903 L

volume = 90.3 mL

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As a technician in a large pharmaceutical research firm, you need to produce 150

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