Beginning at the initial equilibrium, suppose the \' Bank of Canada increases th

Question

Beginning at the initial equilibrium, suppose the ' Bank of Canada increases the money supply. What happens in the money market, and what happens to desired investment expenditure? b Beginning in the initial equilibrium, suppose there is 3 reduction in the demand for money (caused, perhaps, by bonds becoming more attractive to firms and households). What happens in the money market, and what happens to desired investment expenditure? Explain why an increase in money supply can have the same effects on desired investment expenditure as a reduction in money demand.

Explanation / Answer

The midpoint is when the moles of strong acid added = ½ moles of base B initially in the flask. In other words, at the midpoint, half the analyte has been titrated.Graphically, the midpoint is the first point at which the curve has zero slope. At the midpoint, pOH = pKb. Hence from the Y-axis we can note the pH at midpoint(first point at which the curve has zero slope i.e. most horizontal).From that we calculate pOH= 14-pH.This pOH=pKb.Thus we get Kb.

For the above graph at pH =6,the graph looks most hortizontal to x-axis,thus it is the midpoint so pOH=14-6= 8.

hence Kb=10^-7.

Weak base + HCL----->(Conjugate Base )+ H3O.

The equivalence point is defined as the point where the moles of strong acid added = initial moles of base B in solution. Graphically, the equivalence point is where the curve is most vertical.

It is apparent by studying a graph that the equivalence point is distinctly different from the midpoint. On the curve, the equivalence point is located where the graph is most steep. There is a fast and abrupt change of pH around this point, which can be observed by the color change the takes place during titration.

At the equivalence point, an ICE table is required to determine volume and acidity. At this point in the titration, however, the reaction is flipped. This is because the base B has been fully titrated, which means adding more titrant will not yield the same products. The reaction goes backwards.

At the equivalence point, there is no more of base B. Hence, “reactant” is now considered the BH+ that formed from titrating B with strong acid. When calculating [BH+], do not forget to divide number of moles by the volume of base analyte plus titrant added.

Because the neutralization of the starting base is complete, the solution becomes increasingly acidic from this point on (as more acidic titrant is added. This is indicated by the hydronium in the product.

BH+ + H2O---->B + H30.

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