Calculate the molar solubility of SrF_2(K_sp = 4 3 x 10 ^-9) in in water 0.010 M

Question

Calculate the molar solubility of SrF_2(K_sp = 4 3 x 10 ^-9) in in water 0.010 M NaF_2 Will a precipitate of BaSO_4(s) form when 100 mL of 4 0 times 10 3 M BaCl_2(aq) and 300 mL of 6.0 times 10^-4 M Na_2SO_4(aq) are mixed? Explain (Kw(BaSO_4)=1 1 times 10^-10 What is the systematic name for each of the following coordination compounds Cs[FeCI_4] [V(H_2O)4(en)](NO_2)_3 [Co(NH_3)_4Br(l)]CIO_4 [Mn(en)_2(NO_3)_2]PO_4 Write the formula for each of the following compounds. Tetraammineplatinum(ll) Nitrite Sodium hexachloroferrate(ll) Tris(ethylenediamine)platinum(IV) Sulfate TriamminetricyanoNiobium(IV)lodide

Explanation / Answer

2-

(a) Ksp = [Sr2+][F-]^2

let x amount of salt is in solution

4.3 x 10^-9 = (x)(2x)^2

x = 1.02 x 10^-3 M

So molar solubility of SrF2 in water is 1.02 x 10^-3 M

(b) with [F-] = 0.01 M

4.3 x 10^-9 = (x)(0.01)^2

x = 4.3 x 10^-5 M

So molar solubility of SrF2 in 0.010 M NaF is 4.3 x 10^-5 M

3-

[Ba2+] = 4 x 10^-3 x 100/400 = 0.001 M

[SO4^2-] = 6 x 10^-4 x 300/400 = 0.00045 M

Qsp = [Ba2+][SO4^2-] = (0.001)(0.00045) = 4.5 x 10^-7 M

here, Qsp > Ksp ; So precipitation would occur

4-

Naming of coordination compound

(a) Cs[FeCl4] = Cesiumtetrachloroferrite(III)

(b) [V(H2O)4(en)](NO2)3 = tetraaquabisethylenediaminevanadium (III) nitrate

(c) [Co(NH3)4Br]ClO4 = tetraamminebromocobalt(II) chlorate

(d) [Mn(en)2(NO3)2]PO4 = bisethylenediaminedinitromanaganese(V) phosphate

5-

Formula for compounds

(a) [Pt(NH3)4]NO2

(b) Na[Fe(Cl)6]

(c) [Pt(en)3](SO4)2

(d) [Nb(NH3)3(CN)3]I

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