sapling leaming An experiment was performed to test the relative activities of f

Question

sapling leaming An experiment was performed to test the relative activities of four metals, A, B. C, and D. Each solid metal was mixed with solutions of each of the other cations as shown in this chart. The results were n eaoashown in this chart. The results were Al) B D) Y Y N indicated as follows B (aq For example, when A(aq) was mixed with B(s) a reaction occured. C(a) D (aq Y = yes a reaction occured N=n0 a reaction did not occur Use this data to rank the neutral metals according to their activity Most reactive Least reactive C B D

Explanation / Answer

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Formula: C12H22O11 for Sugar

Molar mass: 342.2965 g/mol

1 mole of sugar gives out 6 moles of CO2 with molar mass = 44 g/mol.

So, 3.4 g of CO2 will be produced from =3.4*6*44/342.3 g = 2.62 g

2.62 g of sugar was in 4.5 g of mixture of salt and sugar.

quantity of NaCl = 4.5 - 2.62 g = 1.88 g

% of NaCl = 100*1.88/4.5 =41.78%

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2S2O32-(aq) + I3- = S4O62- (aq) + 3I-

WE can use the equation V1S1 = V2S2, where V is the volume and S is the molarity; 1 and 2 denote for the species.

Here, V1 = 38.6 mL and S1 =0.200 M for the thiosulfate.

V2 = 20.0 mL and S2 =? for the I3-

S2= 38.6*0.2/20.0 = 0.386 M

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Zn(s) + 2HCl (aq) = ZnCl2(aq) + H2(g)

Atomic weight of Zn = 65.38 g

So, 4.85 g of zinc = 4.85/65.38 = 0.074 mols

1 mole of Zn reacts with 2 moles of HCl

So, 0.074 mol will require 2*0.074 mols of HCl =0.148 mols.

1000 mL 1 M HCl = 1 mol of HCl

So, 0.148 mols of HCl = 0.148*1000/6 =24.66 mL

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