I need help with Questions 2 & 3. .50.00 ml of an unknown monoprotic acid is tit

Question

I need help with Questions 2 & 3.

.50.00 ml of an unknown monoprotic acid is titrated wih 0.132 M NaoH. takes f Na 25.25 mL of base to reach the equivalence point, Calculate the concentration of the a 3. Suppose your bb partner accidentally records the value ofile standard H,so,sohution as0.017s instead of 0ITS M. Assuming coher emees are used in this experimenk made wit the concentration of the vnknown acid be a bigger by a factor of 10 bo smaller by a factor of 10 c) unaffected by the calculation Explain your answer.

Explanation / Answer

2) Acid     base

    M1V1 = M2V2

M1 = M2 * V2 /V1 = 0.132*25.25 / 50 = 0.0666

3) 0.0175/0.175 =1/10

So values will be    ..... molarity of acid decreases by 1/10

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