Estimate the electrical resistivity (in -m) of metal Y containing (1.5250x10^0)

Question

Estimate the electrical resistivity (in -m) of metal Y containing (1.5250x10^0) at% of metal Z at (1.473x10^2) °C, given the following information:

The resistivity of pure Y at 0oC is (1.27x10^-8) .m. The change in resistivity per degree celcius is (5.219x10^-11) .m/C. The resistivity changes with concentration as per the equation: A X1 (1-X1), where A is (1.3480x10^-6) .m and X1is the atom fraction of element Z.

Assume that all of the (1.5250x10^0) at% of metal Z goes into solid solution in metal Y.

As always, use scientific notation in the form X.YZ x 10^n.

Explanation / Answer

Total resistivity = resistivity with temperature + resisitivity with concentrtaion

= (p + aT) + (Ax(1-x))

= (1.27x10^-8) .m + (5.219x10^-11) .m/C x 147.3 C +

(1.3480x10^-6) .m x 0.01525 (1-0.01525))

=2.04x10^-8 + 2.024 x 10^-8

= 4.064x10^-8 -m

=

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