Which of the following is the strongest oxidizing agent? MnO_4^-(aq) The gas OF_

Question

Which of the following is the strongest oxidizing agent? MnO_4^-(aq) The gas OF_2 can be produced from the electrolysis 01 an aqueous solution of KF, as shown in the equation below. OF_2 (g) 2H^+ (aq) + 4e^- rightarrow 2F (aq) E^+ = +2.15 V Using the given standard reduction potential, calculate the amount of OF_2 that ie produced, and the electrode at which the OF_2 is produced, upon the passage of 0.480 faradays through an aqueous KF solution. 26.0 g of OF_2 at the anode. 6 48 g of OF_2 at the anode 6 48 g of OF_2 at the cathode 28.0 g of OF_2 at the cathode How long must a constant current of 50 0 A be passed through an electrolytic ceil containing aqueous Cu^2+ ions to produce 5.00 moles of copper metal?

Explanation / Answer

1. KMnO4 is a very strong oxidising agent with Mn is +7 oxidation state.

2. m = QM/Fz = (0.48x54)/(1x1) = 26 g at the anode because here F- oxidised to OF2. Oxidation takes place at anode.

3. M = (ItM)/FZ

t =( 5 x 96500x2)/(50x1) = 5.36 hours.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.