I\'ll should you my work with how I solved the problem with just the two reactan

Question

I'll should you my work with how I solved the problem with just the two reactants. It confused me, so if you could solve this and tell me exactly how and where you get the answers that would be great (: thanks and this is all the information given to me want t nemmn c. 14. Henry's Lawhifethest relationkbilicenca esvap cian eich nemo,004 Increasing the temperature of a reaction system that is will shift the position of chemical equilibrium towards 14. Henry's Law predicts that the solublity of a gas in a liquid inereise with its pariarry and at equilibrium equilibium Explain Henry's Law in relation to Le Châtelier's Principle. e value of Keq for the reaction between water vapor and dichlorine monoxide, H20gt th Cl20 (g) 2HOCI(g) is 0.0900 at 25 °C. Determine the equil three compounds if the starting concentrations of both reactants are 0.00432M and na HOCl is present. v 0 at 25 °C. Determine the equilibrium concentrations ona is e 6. Two cubic containers (seen in the figure below) contain the same quantity of gas at the same temperature. Which cube contains gas with more entropy? If the sample on the right below is left unchanged, but the sample on the left below is cooled so that it condenses, which sample has the higher entropy? 17. Identify the processes as spontaneous or nonspontaneous: i A photovoltaic cell in a solar panel producing elegtricityp A photovoltaic cell in a solar panel producing electricity oon fuom a latex party balloo

Explanation / Answer

15. Keq = [HOCl]^2/[H2O].[Cl2O]

with,

both starting materials and products = 0.00432 M

let x be the change in concentration at equilibrium,

0.09 = (0.00432 + 2x)^2/(0.00432 -x)(0.00432 - x)

3.91x^2 + 0.0181x - 1.70 x 10^-5 = 0

x = 8.01 x 10^-4 M

So the equilibrium concentrations of,

[H2O] = 0.00432 - 8.01 x 10^-4 = 3.52 x 10^-3 M

[Cl2O] = 0.00432 - 8.01 x 10^-4 = 3.52 x 10^-3 M

[HOCl] = 0.00432 + 2 x 8.01 x 10^-4 = 0.00592 M

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.