The first step in the reaction of Alka-Seltzer with stomach acid consists of one

Question

The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO_3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H_2CO_3), and one mole of sodium chloride (NaCl). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 4 mol of NaHCO_3 and 6 mol of HCl. Which of the two reactants limits the number of moles of H_2CO_3 that can be made? HCl NaHCO_3 How much excess reactant remains after the reaction?

Explanation / Answer

NaHCO3 + HCl ----> H2CO3 + NaCl

As per the balanced reaction ; NaHCO3 & HCl reacts in the molar ratio of 1:1

Thus, NaHCO3 is the limiting ragent and HCl is the reactant in excess of 2 moles

Thus, moles of H2CO3 produced = moles of NaHCO3 reacting = 4

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