AlBr3(s) (double arrow) Al(s) + 3/2 Br2(l) I was given these answers to study fo

Question

AlBr3(s) (double arrow) Al(s) + 3/2 Br2(l)

I was given these answers to study for my test but I do not understand why? Can you please explain Thank

We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1. 2 Al + Br2 (double arrow) 2 AlBr2 k1 = (1/k)2

2 Al +3/2 Br2 (double arrow) AlBr3 k2 = 1/k

3. 2 AlBr3 (double arrow) 2 Al + 3 Br2 k3 = k2

Explanation / Answer

AlBr3 <--> Al + 3/2Br2

1)

this is essentially: inverted ( K must be divided)

it is also multiplied by 2, it must go to the second power

overall change -- K = (1/K)^2

2

this is inverted only, therefore, ou must invert K

that is

K = 1/K

3)

this is only 2x the original reaction, overall K change is ^2 power so

K = K^2

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