The same study reported that the following reaction also tends to go forward: Wh
ID: 959837 • Letter: T
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The same study reported that the following reaction also tends to go forward: Which is the stronger arid. H,S or AsH,? Is this in agreement with the general trends for binary adds? What is the usual rationalization for this trend? What might complicate the picture from this rationalization? In class today, I made a mistake in my equations illustrating the solvent system for non- protic solvents Instead of using BrF, as. a solvent, 1 wrote BF, as the solvent I then explained what was going on with some dot showing a P transfer This just shows you can make up equations that look ok but aren't representative of what actually happens in nature Explain the following equation in terms of the solvent system definition, and draw dot to illustrate what the reactants and products are Is the reaction still a fluoride transfer? Do you have any ideas of why this reaction is more plausible than the one I wrote in class, where BF, was the solvent?Explanation / Answer
3. Looking at the given reaction equation we can say that, H2S is a stronger acid than AsH3. Sulfur being more electronegative will be able to stabilize the negative charge formed after the H2S molecule looses an hydrogen from it by an acid-base reaction. Thus the trend shown here is alright with the expectation. The complication in the picture may arise If in case we are to consider the second ionization of H2S that is HS- loosing a proton. This reaction is less likely and hence the HS- is less acidic.
4. BrF3 can act as a fluoride ion donor easily since the central atom Br is electronegative enough to push the F- from it. On the other hand, in case of BF3, boron is not electronegative and would infact be an electron acceptor in a reaction rather than acting as a donor. Thus usings BF3 instead of BrF3 is inappropriate and incorrect.
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