Please help me do this and EXPLAIN WHY BECAUSE I DONT KNOW HOW TO GET THERE The

Question

Please help me do this and EXPLAIN WHY BECAUSE I DONT KNOW HOW TO GET THERE

The answer for these question are:

30, B Weekly basic

31, A Benzoic Acid pk1 =4.20

32, B 2.45

33, A 3.52*10^-3

34, C 2.31*10^-6

35, B sodium hydrogen succinate(II) and sodium cuccinate (III)

36, C 16.7mL

Section Name 2016 Exam0201 HNO2, is 7.1 x 10. Characterize a NH4NO2(aq) solution. A) Weakly acidic The K, of ammonia, NH3, is 1.8 x 10sand the Ka of nitrous acid, C)neutral B) Weakly basic 31. Choose the best weak acid to make a pH = 4.0 buffer. A) Benzoic Acid pK: = 4.20 B) Arsenic Acid p C) Butanoic Acid pK1 = 4.82 D) Chloroacetic acid pKi = 2.87 ki-2.24, Pk2-6.96 K: = 2.24, PK2 = 6.96 Answer questions 32-36 about a 0.20M succinic acid solution pk1 = 4.21 K1 = 6.21 x 10-5 pk2 = 5.64, K2 = 2.31 x 10-6 Ho I. succinic acid OH 32.) What is the pH of the solution? ) 14 8)2.45 65.65 )7.35 95 A) 1.41 33.) What is the concentration of hydrogen succinate in the solution? A) [3.52 x 10-3] B) [1.01 x 10's] C) [6.23 x 10-5] Ho- 34.) What is the concentration of succinate dianion in the solution? II. hydrogen succinate A) [3.5 x 10.3] B) [ 1.0 x 10-5] (C))2.31 x 10-6] onc, o III. succinate 35.) Which of the following could be used to make a pH = 6.00 buffer (roman numerals reference dianion structures shown at right above) with capacity for both acid and base? A) succinic acid (I) and sodium hydrogen succinate (II) B) sodium hydrogen succinate (II) and sodium succinate (III) ) succinic acid (1) and sodium succinate (III) D) either A or B 36. How many mL of 3.00M NaOH could 125 mL of 0.200M succinic acid nuetralize? A 62.5 mLB) 25.3 ml 6.7 mL D) 125 mL Page 5 of 9

Explanation / Answer

30, B Weekly basic SINCE amonia is strong base and HNO2 is weak acid their salt will hydrolised and became basic

31, A Benzoic Acid pk1 =4.20, according to henderson equation half nutalisation of acid give the buffer pH = pk1. since Benzoic Acid pk1 is nearer to 4 this is appropiate

32, B 2.45

pH =0.5 ( pk1 - log C ) c = concentration

33, A 3.52*10^-3

concentration of hydrogen succinate = ( k1 * concentration of succinic acid )0.5

34, C 2.31*10^-6

full diccocation take place so concentration = K2

35, B sodium hydrogen succinate(II) and sodium cuccinate (III)

buffer of pH 6 need complet dissociaotion of succinic acid so hydrogen salt are rule out

36, C 16.7mL

since it is dibasic acid so dissociation of this acid give double concentration of H+ I.E 2* 0.2 =.4

V1S1 = V2S2

V2 = 125 , S2 = .4 , S1 = 3 SO, V1 =?

V1 = 16.7mL

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.