Calculate the standard entropy, DeltaSdegree_rxn. of the following reaction at 2

Question

Calculate the standard entropy, DeltaSdegree_rxn. of the following reaction at 25.0 degree C using the data in this table. The standard enthalpy of the reaction, DeltaHdegree, xni is -44.2 kJmiddot mol^-1. C_2H_4(g) + H_2O(l) rightarrow C_2H_5OH(l) DeltaS_rxndegree = Then, calculate the standard Gibbs free energy of the reaction, DeltaGdegree_rxn. DeltaG_rxndegree = Finally, determine which direction the reaction is spontaneous as written at 25.0 degree C and standard pressure. forward reverse both neither

Explanation / Answer

delta S of the reaction = deltaS of the reactant - deltaS of the products

= [161.04 J / mol-K] - [219.2 J/mol-K + 69.91 J/mol-K]

= -128.07 J mol-1 K-1

Part B

use the equation

delta G = deltaH - TdeltaS

deltaS = -128.07 J mol-1 K-1 , convert in to kilojoules = -0.128 kJ mol-1 K-1

deltaH is given -44.2 kJ/mol

T = 273 +25 = 298k

put all these values in the above equation

deltaG = -44.2 kJ/mol - 298K (-0.128 kJ mol-1 K-1)

= -44.2 kJ/mol + 38.164 kJ / mol

= -6.036 kJ/mol

Part c

delta G = -ve means reaction is favoured for farward direction

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.