Experiment 30 Report Sheet Vitamin C Analysis Desk No. A. Preparation of the K1O

Question

Experiment 30 Report Sheet Vitamin C Analysis Desk No. A. Preparation of the K1O, Primary Standard Cakculate the mass of KIO, (molar mass 214.02 g/mol) required for Part A.1. See Prelaboratory Assignment, question 2. 1. Mass of weighing paper (g) 2. Mass of weighing paper plane KIO, (g) 3. Mass of KIO, (g) 4. Moles of KIO, (mol) s. Molar concentration of KIO, solution (moVi)i 163 B. Sample Preparation Sample name: Trial I Trial 2 Trial 3 1. Vitamin C tablet Mass of tablet )lale Mass of sample analyzed (g) Fresh fruit sample Mass of flask (2) Mass of flask plus sample (g) Mass of sample (g) 3. Fresh vegetable sample Mass of sample (g) C. Vitamin C Analysis Trial I Trial 2 Trial 3 I. Buret reading, initial (ml) 2. Buret reading, final (ml) 3. Volume of KIO, added (ml.) 4. Moles of 1O, dispensed (mol) Experiment 30 347

Explanation / Answer

4.

Moles of IO3- dispensed =

Trial1..................................{ ( 18.8 x .00101 ) / 1000 } = 1.8988 x 10-5

Trial 2.................................{(19.1 x 0.00101) / 1000} = 1.9291 x 10-5  

Trial 3................................{( 19 .1 x 0.00101 ) / 1000 } = 1.9291 x 10-5

5.

Moles of I3- produced = 3 ( moles of IO3-  dispensed )......., as per stoichiometric equation given

Trial 1 ..................5.6964 x 10-5

Trial 2..................5.7873 x 10-5

Trial 3 ................ 5.7873 x 10-5

6.Moles of C6H8 O6 in the sample

= { Vol (L ) of KIO3 x moles of KIO3 / L x 3 I3- }

Trial 1 ..........( 0.0188 x 0.00101 x 5.6964 x 10-5 ) = 1.08 x 10-9

trial 2 ...........( 0.0191 x 0.00101 x 5.7873 x 10-5 ) = 1.12 x 10-9

trial 3........... ( 0.0191 x 0.00101 x 5.7873 x 10-5 ) = 1.12 x 10-9

6.

Mass of C6 H8 O6 in sample in gms. = No.of moles x molar mass

................................................................ =( No. of moles of C6 H8 O6 ) x 176.1

trial 1......................1.902 x 10-7 gms.

trial 2......................1.97 x 10-7 gms.

trial 3......................1.97 x 10-7 gms.

8.

Mass ratio = ( mgms of C6H8 O6 ) / 100 gms of sample

trial 1...................................0.1419

trial 2...................................0.1470

trial 3...................................0.1470

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