a) Calculate Hº (in kJ) for the following reaction at 298 K: 2CO 2 (g) +4H 2 O(l

Question

a) Calculate Hº (in kJ) for the following reaction at 298 K:

2CO2(g) +4H2O(l) 2CH3OH(l) + 3O2(g)

Use the data in Appendix II (Tro); Appendix 4 (Zumdahl)

b) Calculate Sº (in J/K) at 298 K for :

2CO2(g) +4H2O(l) 2CH3OH(l) + 3O2(g)

c) Use Gº =Hº -TSº to calculate G (in kJ) at 298 K for :

2CO2(g) +4H2O(l) 2CH3OH(l) + 3O2(g)

d) If the above reaction could be done at 3011 K, what would be your estimate for Gº (in kJ) at this elevated temperature? Use Gº =Hº -TSº and assume Hº and Sº are independent of temperature.

thanks!!!

Explanation / Answer

a)

2CO2(g) +4H2O(l) 2CH3OH(l) + 3O2(g)

Hrxn = (2*-238.4 + 3*0) - (2*-393.5 + 4*-285.8 )

HRxn = 1453.4 kJ/mol

b)

SRxn = Sproducts - sreactants

S =(2*126.8 + 3*205.0) - (2*213.6 + 4*69.9 )

S = 161.8 J/molK

c)

G = H - TS = 1453400 - 298* 161.8

G = 1405183.6 J

G = 1405.184 kJ/mol

d)

G = H - TS = 1453400 - 3011* 161.8

G = 966220.2 kJ/mol

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