When solutions of silver nitrate and magnesium chloride are mixed, silver chlori

Question

When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+MgCl2(aq)2AgCl(s)+Mg(NO3)2(aq)

Part A: What mass of silver chloride can be produced from 1.83 L of a 0.120 M solution of silver nitrate (mass of AgCl)? Express your answer with the appropriate units.

Part B: The reaction described in Part A required 3.93 L of magnesium chloride. What is the concentration of this magnesium chloride solution? Express your answer with the appropriate units.

Explanation / Answer

AgCl

mol of Ag = MV = 1.83*0.12= 0.2196 mol of Ag+

then

mass of Agcl = 0.2196*143.32 = 31.473 g of AgCl could be produced

B)

V = 3.93 L of MgCl2

we need 0.2196 mol of Cl-

that is

0.2196 *2 = 0.4392 mol of MgCl2

[MgCl2] = mol/V = 0.4392/(3.93) = 0.11175 M

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