LAB REPORT Include all sections for you report as listed in the syllabus. Rememb
ID: 963997 • Letter: L
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LAB REPORT Include all sections for you report as listed in the syllabus. Remember be sure to show a sample of each kind of calculation. Calculations Guide for Analysis Section of your Lab Report (1) The molar mass of KHC,H,O, (KHP) is 204.23 g/mole. Calculate the number of moles of KHC,H,O, and HC,H,O, in each sample weighed. As you can see below, there is a 1:1 molar ratio between the two species. KHC,I 1,04 (s) K. (aq) + HC,H404 (aq) (2) At the equivalence point, the number of moles of OH is equal to the number of moles of HC,H,O,. Calculate the moles of HC,H O, for each trial. Then use the volume of hydroxide for each trial to calculate the molarity of the hydroxide ion in the filtrate for each trial. (3) The dissociation equation for calcium hydroxide is : Ca(OH)2(s) Ca2+ (aq) + 2 OH (aq) -X +x In saturated solution, we can assume that |Ca21 understand this concept before proceeding! 2[OH]. Be sure you Substituting values for (OH] and (Ca2'] in the K,p expression we can calculate the Kp experimentally. Calculate a value for Kip for each trial and then calculate an average K Report the temperature you measured in step (1). (4 From your average Ksp value, calculate the solubility of calcium hydroxide in moles/L and grams/I.Explanation / Answer
I will do a calculation sample from one of your results so you can have an idea.
first the moles of KHP:
moles = 0.064 / 204.23 = 3.13x10-4 moles
These moles are the same moles of the ftalate ion, and in the equivalence point, is the moles of the base [OH]. The concentration would be:
[OH] = 3.13x10-4 / 0.0464 = 6.75x10-3 M
With this, the [Ca2+] = 6.75x10-3 / 2 = 3.375x10-3 M
Ksp = 3.375x10-3 * (6.75x10-3)2
Ksp = 1.54x10-7
The solubility in mol/L is the concentration of Ca2+, but in g/L you will use the molecular weight of Ca(OH)2 which is 74.093 g/mol so:
s = 3.375x10-3 mol/L * 74.093 g/mol = 0.25 g/L
Now, do the same for the other values and take the average of Ksp and calculate the solubility.
Hope this helps
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