When an ion-selective electrode for X+ was immersed in 0.0730 M XCl, the measure

Question

When an ion-selective electrode for X+ was immersed in 0.0730 M XCl, the measured potential was 0.0330 V. What is the concentration of X+ when the potential is 0.0480 V? Assume that the electrode follows the Nernst Equation, the temperature is 25 degrees Celsius, and that the activity coefficient of X+ is 1.
[X+] =

Thank you so much in advance! I have worked out this problem, but I am not sure where to go after I plug in all the data. Please show your work so I can apply this solution to other problems in the future.

Explanation / Answer

E =E0 - 0.0595/n ln(X+)

When we draw graph for E and ln(X+) , the intercept is E0 and slope is -0.0595 /n

Here n=1

0.0330 = E0 -(0.0595/n) ln(0.0730) ----------(1)

0.0480 = E0 -(0.0595/n) ln(X) -----------(2)

(2) -(1) :

0.0480 -0.0330 = (0.0595/1) x (ln(0.0730)  - ln(X) )

0.0150 = 0.0595 x (-2.617 - ln(X))

ln(X)= -2.617 - (0.0150/0.0595 )

  ln(X) = -2.8694

X = exp( -2.8694)

= 0.0567

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