please help me in part B Chrome File Edit View History Bookmarks People Window H
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please help me in part B
Chrome File Edit View History Bookmarks People Window Help Thu 8:40 PM a Online ntegral Calc x Google Translate x myBoiseState we x MPearson's MyLab& x Masteringchemistry x Masteringchemistry x Chegg Study Guia x what mass of silver x What mass of silverx -> https://session.masteringchemistry.com/myct/itemview?assignmentProblemID=59145596&offset-next; CHEM 111-001 Spring 2016 MMC Homework Chapter 09Solution Stoichiometry ABP Help | Close Resources « previous | 2 of 20 next » Solution Stoichiometry Part A What mass of silver chloride can be produced from 1.01 L of a 0.162 M solution of silver nitrate? To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is equal to the concentration in moles per liter M = mol/L Express your answer with the appropriate units mass of AgCl = 23.4 g Submit Hints My Answers Give Up Review Part Correct Significant Figures Feedback: Your answer 23.46 g was either rounded differently or used a different number of significant figures than required for this part. Part B The reaction described in Part A required 3.85 L of potassium chloride. What is the concentration of this potassium chloride solution? Express your answer with the appropriate units 23.4g Submit Hints My Answers Give Up Review Part Incorrect Try Again; 5 attempts remaining Enter your answer using dimensions of chemical concentration ide Feedba ContinueExplanation / Answer
AgNO3 + KCl ---> AgCl + KNO3
hence potassium chlodire moles = silver nitrate moles
silver nitrate moles = M x V = 0.162x 1= 0.162
KCl moles = 0.162
we were given KCl volume = 3.85 L
hence Molarity of KCl = moles/vol 0.162 /3.85 = 0.042 M
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