University of Wisconsin W x C www.saplinglearning.com/ibiscms/mod/ibis view.php?

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University of Wisconsin W x C www.saplinglearning.com/ibiscms/mod/ibis view.php?id 2478009 Apps Timesheet Schooldude Ma Printing Q Quizlet Life LaunchPad P Pandora Chegg UWW D2L Sapling Learning USPS nteract Question 16 of 28 95 Map sapling ea 95 At a certain temperature, the Kp for the decomposition of H2S is 0.810. 100 H, g) S 100 tially, only H2S is present at a pressure of 0.221 atm in a closed container. What is the total pressure in the container at equilibrium? 93 Number 90 atm 100 65 80 80 100 85 Previous 2 Give Up & View Solution Check Answer Next Exit Hin NE HE Search the web and Windows Molecular Geometry Due Date: Points Possible 10 Grade Category GI Description: Policies: You can check your an You can view solutions up on any question. You can keep trying to you get it right or give You lose 5% of the po in your question for ea answer O Help With This Topic O Web Help & Videos O Technical Support ar 6:26 PM 4/8/2016

Explanation / Answer

Kp = 0.81

Kp = H2*S/(H2S)

H2S = 0.221-x

S = 0 + x

H2 = 0 + x

0.81 = x*x/(0.221-x)

x^2 = -0.81x +0.221*0.81

x^2+ 0.81x - 0.221*0.81= 0

x = 0.1332

H2S = 0.221-0.1332 = 0.121

S = 0 + x = 0.1332

H2 = 0 + x = 0.1332

PT = 0.121+0.1332+0.1332 = 0.3874 atm

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