Consider equimolar samples of different ideal gases at the same volume and tempe
ID: 966522 • Letter: C
Question
Consider equimolar samples of different ideal gases at the same volume and temperature.Gas A has a higher molar mass than gas B. Compare the pressures. Compare the rms speeds. Compare the average kinetic energies Consider equimolar samples of the same ideal gas at the same volume, but different temperatures. Sample C is at a higher temperature than sample D. Compare the pressures. Compare the rms speeds. ompare the average kinetic energies.Consider equimolar samples of the same ideal gas at the same temperature, but different volumes Sample E has a larger volume than sample F. Compare the pressures. Compare the rms speeds. Compare the average kinetic energiesExplanation / Answer
According to ideal gas equation, PV = nRT then P1V1/n1T1 = P2V2/n2T2
from given conditions n1 = n2 and V1 = V2, T1 = T2 then P1 = P2
Pressure of Gas A = Gas B
Kinetic energy of gas depends upon temperature hence K.E of A = K.E of B
rms speed is inversely proportional to square root of molar mass.
so Molar mass high means rms speed less
rms speed of A < rms speed of B
According to ideal gas equation, PV = nRT then P3V3/n3T3 = P4V4/n4T4
from given conditions n3 = n4 and V3 = V4, T3 > T4 then P3 > P4
Pressure of Gas C > Gas D
Kinetic energy of gas depends upon temperature hence K.E of C > K.E of D
rms speeds directly proportional to temperature so rms speed of C > rms speed of D
According to ideal gas equation, PV = nRT then P5V5/n5T5 = P6V6/n6T6
from given conditions n5 = n6,T5 = T6 and V5 > V6, then P5 < P6
Pressure of Gas E < Gas F
Kinetic energy of gas depends upon temperature hence K.E of E = K.E of F
rms speeds directly proportional to temperature so rms speed of E = rms speed of F
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