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Given that 4NH_3(g) + 5O_2(g) rightarrow 4NO(g) + 6H_2O(g), if 4.5 moles of NH_3

ID: 967063 • Letter: G

Question

Given that 4NH_3(g) + 5O_2(g) rightarrow 4NO(g) + 6H_2O(g), if 4.5 moles of NH_3 react with sufficient oxygen, how many moles of H_2O will be formed? 4.0 4.5 6.0 6.8 A solution contains the label 0.2 M KNO_3. What is the correct interpretation of this concentration? There are 0.2 moles of KNO_3 in 100 mL of solution. There are 0.2 g of KNO_3 in 100 mL of solution. There are 0.2 molecules of KNO_3 in 1 L of solution. There are 0.2 g of KNO_3 in 1 L of solution. There are 0.2 moles of KNO_3 in 1 L of solution. Nitrogen and hydrogen react together to form ammonia according to the equation: N_2(g) + 3 H_2(g) rightarrow 2 NH_3(g) Determine how many grams of hydrogen would be required to react with 25.2 g of nitrogen. 1.82 g 3.64 g 5.45 g 1.34g 0.891 If the theoretical yield for the aspirin synthesis is 54.9 g, and 51.3 g are actually obtained, the percent yield is: 0.934% 93.4% 10 7% 3.60% not enough information given A 4.691 g sample of MgCl_2 is dissolved in enough water to give 750. mL of solution. What is the MgCl_2 concentration in this solution? 3.70 Times 10^-2 M 1.05 Times 10^-2 6.57 Times 10^-2 M 4.93 Times 10^-2 M 0.131 M Calcium chloride is used to melt ice and snow on roads and sidewalks and to remove water from organic liquids. Calculate the molarity of a solution prepared by diluting 165 mL of 0.688 M calcium chloride to 925.0 mL. 3.86 M 0.743 M 0.222 M 0.123 M 0.114 M

Explanation / Answer

12.

ratio:

6H2O/4NH3 = 6/4 ; H2O:NH3

1.5

4.5 mol * Ratio = mol of NH3

4.5*1.5 = 6.75 mol of H2O formed --> 6.8 mol of H2O rounded

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