Name Maria 7 CHM 112 Solutions Lab DATA fa Saturated Solution of NaCI Mass of ev

Question

Name Maria 7 CHM 112 Solutions Lab DATA fa Saturated Solution of NaCI Mass of evaporating dish Mass of evaporating dish and solution 0. 57 Mass of evaporating dish and Nacng 63 53.448 Volume of solution 10.00 ml Mass Volume Moles Solute3.eag Solute 3.iaaa Nac .su mol Solvent 7.8S moi Molar concentration of NaCI Molality of NaCI Mole fraction of NaCl Mole fraction of H2O Weight % NaCl .10m s x1 13 m -21 Show calculations for all steps using proper units and math operations! Put the calculations on a separate piece of paper. net Come

Explanation / Answer

A: mass of solution = 60.357 g - 49.336 g = 11.021 g

mass of solute NaCl = 52.498 g - 49.336 g = 3.162 g

Moles of solute NaCl = mass / molar mass = 3.162 g / 23.0 g/mol = 0.1375 mol (correct answer)

Mass of solvent, H2O = mass of solution - mass of NaCl = 11.021 g - 3.162 = 7.859 g

Moles of solvent H2O = mass / molar mass = 7.859 g / 18.0 g/mol = 0.4366 mol (correct answer)

mass of solution = 60.357 g - 49.336 g = 11.021 g

moles of solution = 0.1375 mol + 0.4366 mol = 0.5741 mol  (correct answer)

----------------------------------------------------------------------

Molar concentration of NaCl = moles of NaCl / V(L) =  0.1375 mol / 0.010 L = 13.7 mol/L

Molality of NaCl = moles of NaCl / mass of solvent,H2O

= (0.1375 mol / 7.859 g) x 1000 g/Kg = 17.5 m (correct answer)

Mole fraction of NaCl = (moles of NaCl) / (moles of NaCl + moles of H2O)

=  0.1375 mol / (0.1375 mol + 0.4366 mol) = 0.240 (correct answer)

Mole fraction of H2O = (moles of H2O) / (moles of NaCl + moles of H2O)

= 0.4366 mol / (0.1375 mol + 0.4366 mol) = 0.760 (correct answer)

Weight percent of NaCl = (3.162 g / 11.021 g) x 100 = 28.7 W% (answer)

Volume of solution is required to calulate for KNO3.

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.