Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25 degree

Question

Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25 degree C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine deltaH rxn for^C(diamond)^rightarrow C(graphite) with equations from the following list:^C(diamond) C_(diamond) +)_2(g) rightarrow CO_2(g) 2C02(g) rightarrow 2 CO(g) + 02(g)^C_(graphic) + O_2(g) rightarrow C02(g) 2 CO(g) rightarrow C(graphire) + CO2(g) delta H = -395.4 kJ delta H = 566.0 kJ delta H = -393.5 kJ deltaH = -172.5 kJ

Explanation / Answer

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C (s, diamond) ---> C (s, graphite)         H° = -1.9 kJ

Hoverall = -1.9 kJ

C (s, graphite) + O2(g) ---> CO2(g) H° = -393.5 kJ C (s, diamond) + O2(g) ---> CO2(g) H° = -395.4 kJ

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