Experiment # 9 Page 10 of 10 FINAL QUESTIONS The NaOH titrant in this experiment

Question

Experiment # 9 Page 10 of 10 FINAL QUESTIONS The NaOH titrant in this experiment was prepared to be approximately 0.1 M and then was standardizedto determine iteatscentration What nossible reasons could there be for standardized to determine its exact concentration. What possible reasons could there be for 1· not simply weighing the solid NaOH, dissolving to a known volume and calculating its molarity? 2. Carbon dioxide from the air dissolves in water, forming small amounts of carbonic acid, ly! H2COs, and causing the water to be slightly acidic. Would this tend to make your titration volume in part A of this experiment too large, too small or unchanged? Explain brief

Explanation / Answer

1.

Solid NaOH is a caustic soda and special care is required to prepare a solution of NaOH because considerable heat is liberated by the exothermic reaction.

If you need to prepare a solution is less difficult and dangerous to use a concentrated solution and to dilute in order to prepare a NaOH with 0.1 M concentration.

2. The presence of CO2 forms H2CO3 and makes water to be more acidic, then this may cause titration to be a tiny longer but not too much because H2CO3 is a weak acid.

H2CO3 <----> H+ + HCO3 pKa 1=6.37 weak acid

HCO3 - <----> H+ + CO3 2 pKa2= 10.32 weak acid

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