What will happen to the pH of a Na_2CO_3 solution if a small amount of NaHCO_3 i

Question

What will happen to the pH of a Na_2CO_3 solution if a small amount of NaHCO_3 is added to it? pH will increase because NaHCO_3 is basic when placed in water. pH will not change because NaHCO_3/Na_2CO_3 solution will create a buffer. pH will decrease because added HCO^-_3 will suppress the hydrolysis of CO^2-_3 ions. d. pH will decrease because NaHCO_3 is acidic when placed in water. Which of the following will produce a buffer system? 50 mL 0.10 M HCl and 50 mL 0.20 M K_2C_2O_4 50 ml. 0.10 M HCl and 50 mL 0.20 M NaOH 50 mL 0.10 S1 HCl and 50 mL 0.10 M NH_3 50 mL 0.10 M NaOH and 50 mL 0.10 M KHSO_3 A buffer solution is prepared by combining 100 mL of 0.20 M H_2NNH_2 and 100 mL of 0.40 M H_2NNH_3Cl. What is the pH of this buffer? 5.3 6.5 7.8 9.2 If a small amount of HCl is added to a buffer composed of (CH_3)_2NH and (CH_2)_2NH_2Cl. pH of the buffer will increase Ratio of [CH_3)_2NH]/[(CH_3)_2NH_2^+] will remain the same There will be less (CH_3)_2NH and more

Explanation / Answer

a )   answer : c )

NaHCO3 is acidic salt

HCO3 - < -----------------> H+ + CO3-2

Na2CO3   ---------------> 2Na+   + CO3-2

here common ion CO3-2 supress the dissociation of CO3-2 that means basicity decreases and acidity increases so pH will decreases

b) answer : a

c)

pOH = pKb + log [salt / base]

pOH = 5.89 + log (0.4 x100 / 0.20 x 100)

pOH = 6.19

pH + pOH = 14

pH = 7.80

answer : c ) 7.8

d)

HCl react with base form salt that means base concentration decreases and salt concentration increases

suppose HCl concentration = x

(CH3)2NH   -------------------->(CH3)2NH2Cl

   M -x                                       M + x

so answer : C )

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