Calculate the ratio [NH3]/[NH4+] in ammonia/ammonium chloride buffered solutions

Question

Calculate the ratio [NH3]/[NH4+] in ammonia/ammonium chloride buffered solutions with the following pH values:

YeChegg Study Gu YD CengageBrain-M Application to Repl XApocalyptica - Noin SP2016-CHEM-131 X DExam 4 Problem Sel xD 116 2(1).pdf c Deast.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator-assignment-take what Volumes Ofc :.OWLV2 Online tea x Apps Trinity Universit C Online Integral AA Macmillan Laun . .. Cengage: Chem. . Statistics-Goo. REEF Education SD Stats Trek Formation Enth . TS Life Ascending Chapter 14.1-14.4 References Calculate the ratio [NH3 NH4+in ammonia/ammonium chloride buffered solutions with the following pH values: Question 5 (This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTajp Reader. You should not use the OWLv2 References' Tables to answer this question as the values will not match. Simplify your answer completely.) Question 6 Question 7 a. pH 9.00 NHs] Question 8 Question 9 b. pH- 8.10 NHs] Question 10 Question 11 c, pH 10.70 Question 12 Question 13 d. pH -9.60 NHs] Question 14 Question 15 Question 16 Submit Answer Try Another Version 10 item attempts remaining Question 17 Question 18 Question 19

Explanation / Answer

1) Poh = Pkb + log{[NH4^+]/[NH3]}

Pkb of NH3 = 4.74

Poh = 14 - Ph

Poh = 14 - 9.0 = 5.0

5.0 = 4.74 + log{[NH4^+]/[NH3]}

[NH4^+]/[NH3] = 1.82

2)

Ph = 8.10

Poh = 5.90

5.90 = 4.74 + log{[NH4^+]/[NH3]}

[NH4^+]/[NH3] = 14.45

3) Ph = 10.70

Poh = 3.30

3.30 = 4.74 + log{[NH4^+]/[NH3]}

[NH4^+]/[NH3] = 3.63*10^-2

4)

Ph = 9.60

Poh = 14 - Ph

Poh = 14 - 9.60 = 4.40

4.40 = 4.74 + log{[NH4^+]/[NH3]}

[NH4^+]/[NH3]= 0.46

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