A)What is the oxidation state of sulfur before and after the reaction below? SO
ID: 974853 • Letter: A
Question
A)What is the oxidation state of sulfur before and after the reaction below?
SO32-(aq) + MnO4-(aq) SO42-(aq) + Mn2+(aq)
Before the reaction?
After the reaction?
+5
-5
+4
+1
+6
-2
-4
+3
0
-1
-3
B) What is the oxidation state of copper before and after the reaction below?
2NO3-(aq) + 8H+(aq) + 3Cu(s) 3Cu2+(aq) + 2NO(g) + 4H2O(l)
Before the reaction?
After the reaction?
-1
+5
+2
0
-5
-4
-2
+1
-3
+3
+4
C)What is the oxidation state of nitrogen before and after the reaction below?
2NO3-(aq) + 8H+(aq) + 3Cu(s) 3Cu2+(aq) + 2NO(g) + 4H2O(l)
Before the reaction?
After the reaction?
+5
+4
+3
+2
+1
0
-1
-2
-3
-4
-5
- A. B. C. D. E. F. G. H. I. J. K.Before the reaction?
- A. B. C. D. E. F. G. H. I. J. K.After the reaction?
A.+5
B.-5
C.+4
D.+1
E.+6
F.-2
G.-4
H.+3
I.0
J.-1
K.-3
Explanation / Answer
SO32-(aq) + MnO4-(aq) SO42-(aq) + Mn2+(aq)
in SO32-
x + 3(-2) = -2
X = +4 (before reaction)
in SO42-
x + 4(-2) = -2
X = +6 (after reaction)
2NO3-(aq) + 8H+(aq) + 3Cu(s) 3Cu2+(aq) + 2NO(g) + 4H2O(l)
It is observed from reaction itself before reaction only copper is present. so oxidation state of Cu = 0
After reaction it is observed that Cu+2 so Oxidation state of Cu = +2
in NO3-
x + 3(-2) = -1
x = +5 (before reaction)
in NO
x + (-2) = 0
x = +2 (after reaction)
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