Adenosine monophosphate (AMP) is a regulatory molecule in metabolic processes su

Question

Adenosine monophosphate (AMP) is a regulatory molecule in metabolic processes such as glycolysis and gluconeogenesis. For example, it stimulates the glycolytic enzyme phosphofructokinase, and therefore ATP production, and it inhibits the gluconeogenic enzyme fructose 1,6-bisphosphatase. Adenylate kinase catalyzes the reversible reaction shown here:

During periods of intense activity, when glycolysis is used in the generation of ATP, the reaction lies to the right, decreasing [ADP], generating ATP, and accumulating AMP. However, [ATP] is usually much greater than [ADP], and [ADP] is greater than [AMP]. Determine [AMP] when 3% of the ATP in a hypothetical cell is hydrolyzed to ADP. In this cell, the initial concentration of ATP is 267 ?M, and the total adenine nucleotide concentration (the concentration of ATP, ADP, and AMP) is 362 ?M. The equilibrium constant K is 0.82 What is the concentration of AMP after 3% of the ATP is hydrolyzed to ADP?

Explanation / Answer

ANSWER

ATP + AMP <--------> 2ADP

Equilibrium constant (K) = [ADP]2 / [ATP][AMP]

One mole of ATP recats with one mole of AMP to form 2 moles of ADP

Moles of ATP reacted = 3% of 267 = 267 X 3/100 =8.01

ATP present at Equilibrium = 262 - 8.01 = 258.99

Moles of ADP formed = 2 X 8.01 = 16.02µM

Let there were xµM of AMP initially. 8.01µM of AMP will react with 8.01µM of ATP

K = 0.82 = [16.02]2 / [258.99][x - 8.01]

solving the above equation gives

x = 9.22µM, x is the initial concentration of AMP

Hence concentration of AMP at equilibrium = 9.22 - 8.01 = 1.21µM

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