A student dissolved 10.5 g of NH^4CI in 40 mL of water. The temperature of the w

Question

A student dissolved 10.5 g of NH^4CI in 40 mL of water. The temperature of the water changed from 22.5 degree C to 5.1 degree C. Calculate the enthalpy of hydration of ammonium chloride in J/mol. A student completed the Kool-Aid Spectroscopy lab and obtained the following equation after plotting concentration v_s Absorbance y = 1.74 x + 0.0096 What is the concentration of a sample with an absorbance of 0 44? A galvanic cell is made using Pb(syPb^2+(1.0M) and AI(s)/AI^3+(1 0M). The cell gives a positive reading when Pb is the positive electrode What is the correct cell notation for this system? Enter Pb for lead electrode. Pb^2+ for the lead solution. Al for the alummun electrode and AI3^+ for the aluminum solution.

Explanation / Answer

The equation is :-

y = 1.74x + 0.0096

where y = concentration and x = absorbance

Thus, y = 1.74*0.44 + 0.0096 = 0.7752 M

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