11. In the unbalanced reaction __KClO4(s) __KClO3(s) + __O2(g), is potassium oxi

Question

11. In the unbalanced reaction __KClO4(s) __KClO3(s) + __O2(g), is potassium oxidized or reduced?
a. Oxidized b. Reduced c. Both d. Neither

12. In the unbalanced reaction __KClO4(s) __KClO3(s) + __O2(g), is oxygen oxidized or reduced?
a. Oxidized b. Reduced c. Both d. Neither

13. In the unbalanced reaction __KClO4(s) __KClO3(s) + __O2(g), is chlorine oxidized or reduced?
a. Oxidized b. Reduced c. Both d. Neither

14. When the reaction __KClO4(s) __KClO3(s) + __O2(g) is balanced, the coefficient in front of KClO4(s) will be:
a. 1 b. 2 c. 3 d. 4

15. In the unbalanced reaction __Al(s) + __Cu(NO3)2(aq) __Cu(s) + __Al(NO3)3(aq), is oxygen oxidized or reduced?
a. Oxidized b. Reduced c. Both d. Neither

16. In the unbalanced reaction __Al(s) + __Cu(NO3)2(aq) __Cu(s) + __Al(NO3)3(aq), is aluminum oxidized or reduced?
a. Oxidized b. Reduced c. Both d. Neither
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Explanation / Answer

2 KClO4 -------> 2 KClO3 + O2
1) In both reactants and products oxidation state of K = +1
2) In reactants O2 oxidation state is -2 and in products it became 0 so Oxygen is oxidised.
3) In reactants chlorine oxidation state +7 and in products it became +5 so chlorine is reduced.

2 Al + 3 Cu(NO3)2 ------> 3 Cu + 2 Al(NO3)3
1) In both reactants and products oxidation state of O = -2.
2) IN reactants Al has 0 oxidation state and it became +3 in products so Al oxidized.

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