when I made this test on Sunday evening at 8:50 PM When I made this test on Sund

Question

when I made this test on Sunday evening at 8:50 PM When I made this test on Sunday evening at 8:50PM, April 24,2016 [before my eye operation tomorrow morning (April 25th)] the outside temperature was 37DegreeF and the barometric pressure was 30.18 inches of Hg. From the percent relative humidity at that time, I was able to calculate the partial pressure of water vapor (moisture) in the air to be 22.0 mm Hg. If the partial pressure of nitrogen in the air was 645.0 mm Hg, what was the partial pressure of oxygen in the air at that time? (Helpful conversion Factor: 1 inch = 25.4 mm.)

Explanation / Answer

Total air pressure = 30.18*25.4 = 766.572 mm of Hg = 1.01 atm

Now, total pressure of air = partial pressure of vapor + partial pressure of N2 + partial pressure of O2

or, partial pressure of O2 = 766.572 - 645 - 22 = 99.572 mm of Hg

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.