Consider the following reaction: 2C4F6 --> C8F12 At 375 deg Celcius, the rate co

Question

Consider the following reaction:
2C4F6 --> C8F12
At 375 deg Celcius, the rate constant is 0.0896 L/mol • s. If the initial concentration of C4F6 is 0.200 M, what will it be after 205s? Consider the following reaction:
2C4F6 --> C8F12
At 375 deg Celcius, the rate constant is 0.0896 L/mol • s. If the initial concentration of C4F6 is 0.200 M, what will it be after 205s?
2C4F6 --> C8F12
At 375 deg Celcius, the rate constant is 0.0896 L/mol • s. If the initial concentration of C4F6 is 0.200 M, what will it be after 205s?

Explanation / Answer

rate constant k = 0.0896 L / mol s

this is the second order rate equation based on the rate constant units

1/ [A] = 1/[A0] + kt

where A0 = intial concentration given as 0.2 M

[A] = concentration after205 s

k = rate constant given as 0.0896 L/mol • s

t = time given 205s

plug in all the values in the above equation

1 / [A] = (1 / 0.2 ) + (0.0896 x 205)

1 / [A] = 5 + 18.368

1 / [A] = 23.368

[A] = 1 / 23.368   = 0.043M

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