Given the following information: A sulfuric acid solution contains 5.80 x 10 2 g

Question

Given the following information: A sulfuric acid solution contains 5.80 x 102 g of H2SO4 per liter of solution. The density of the solution is 1.329 g/mL. The mole fraction of the water in the solution is   

0.250

Given the following information: A sulfuric acid solution contains 5.80 x 102 g of H2SO4 per liter of solution. The density of the solution is 1.329 g/mL. The molality of the solution is   

1.50 mol/kg

Given the following information: A sulfuric acid solution contains 580. g of hydrogen sulfate per liter of solution. The density of the solution is 1.329 g/mL. The mole fraction of hydrogen sulfate in the solution is   

Explanation / Answer

m = 580 g of H2SO4

mol = m/MW = 580/98 = 5.92 mol of H2SO4

V = 1 L

mole fraction of solution

mol of i

total mass =D*V = 1000*1.329 = 1329 g

mass of water = 1329- 580 = 749 g of weater

mol water = m/MW = 749/18 = 41.61 mol

total mol = 41.61+5.92

mol frac of acid = 5.92/(41.61+5.92) = 0.12455

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