Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In answering there questions, you may use your textbook, lab or notes from class

ID: 980237 • Letter: I

Question

In answering there questions, you may use your textbook, lab or notes from class You may confer with any other members of the class use your electronic device to search for answer. These questions must be completed and stapled to the back of your laboratory report. A student determined the % water of a hydrate in two trials. The results were as show a below. Determine the average water, and given the list of possibilities in your lab book, which salt was his unknown? Trial # 1 / 55.7 % water Trial #2 / 56.9 % water Assuming that your hydrate selection in part a is correct, determine the % error for the average value When conducting your experiment, you noticed loud popping noises that took place when you heated your hydrate. You believe you may have lost some of the hydrate upon heating. Do you believe the value will be higher, lower, or have no impact on the calculated% water content of your hydrate? Explain. A hydrate weighing 0.460 g, was heated to drive off water. The anhydrous salt remaining weighed 0.390 g. what was the % water in the hydrate?

Explanation / Answer

1. % of Average Experimental Water = 56.3 %

2. Asumming accepted value of the compound is 50% water. (You most select from your textbook)

% Error = (56.3 - 50/50) x 100 = 12.6%

3. Weight of hydrated compound = 0.460 g

Weight of anhydrous compound = 0.390 g

So, weight of water in compound = 0.460 - 0.390 = 0.070 g

% of water = Total mass of water x 100 / Total mass of Hydrate

% of water = (0.070/0.460) x 100 = 15.21 %

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote