The viewing window in a diving suit has an area of roughly 10.0 in ^ 2. If an at
ID: 981818 • Letter: T
Question
The viewing window in a diving suit has an area of roughly 10.0 in ^ 2. If an attempt were made to maintain the pressure on the inside of the suit at 1 atm, what force (lb _ f) would the window have to withstand if the diver descended to a depth of 455 ft. Take the specific gravity of the water to be 1.05 A 1,500 gallon vessel is filled with 4,900 kg of ethylene glycol. How many gallons would this occupy in the vessel What assumption(s) were made in this calculation How long would it take to empty a completely filled 1,500 gallon tank at 300 L/minExplanation / Answer
Area= 10 in2=10*0.06944 ft2
Volume= 0.06944*455 ft3=31.59 ft3
Mass =31.5952*62.4 lb/ft3=1971.54 lb=1971.54*0.4535=894.1kg
Force= mass* accleration due to gravity= 894.1*9.8 N=8762 N=8762*0.2248 =1970 lbf
b) density of ethylene glycol= 1.132 g/cc=1.132 Kg/L
volume of ethylene glycol = mass/ density= 4900/1.132 L=4329 L ( 1 Gallon= 3.78 L)
Volume of ethylene glycol in Gallons= 4329/3.78 =1145 Gallons
c) The densitt of ethylene glycol is asssumed to be 1.132 g/cc
d) 1 Gallon= 3.78 L and hence1500 gal/min= 1500/3.78=397 L
Flow rate= 300 l/min
time = tank capacity/ flow rate= 397/300=1.32 minutes
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